Irod=Irod,com+Md2=112ML2+M(L4)2=112ML2+116ML2=748ML2cap I sub r o d end-sub equals cap I sub r o d comma c o m end-sub plus cap M d squared equals 1 over 12 end-fraction cap M cap L squared plus cap M open paren the fraction with numerator cap L and denominator 4 end-fraction close paren squared equals 1 over 12 end-fraction cap M cap L squared plus 1 over 16 end-fraction cap M cap L squared equals 7 over 48 end-fraction cap M cap L squared
v0vthe fraction with numerator v sub 0 and denominator v end-fraction
connects the ring to a fixed hook at the top of the rod. Another mass
Problem 1: The Sliding and Rolling Bowling Ball (Rigid Body Dynamics) A uniform solid sphere of mass and radius
Always ask if energy, linear momentum, or angular momentum is conserved. Look for symmetries in the system.
a=−fkM=−μga equals the fraction with numerator negative f sub k and denominator cap M end-fraction equals negative mu g
Surprisingly, the velocity is constant despite the continuous application of a constant force. The input force is entirely balanced by the rate of momentum required to accelerate the stationary segments of the rope to speed
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