916 Checkerboard V1 Codehs Fixed !exclusive! -

to create a checkerboard pattern in the top and bottom three rows, while leaving the middle two rows as

(rightIsClear()) turnRight(); move(); turnRight();

According to the official instructions for 9.1.6 Checkerboard, v1 , the grid is structured with the top three rows and the bottom three rows filled with an alternating pattern of 1 s and 0 s. The middle two rows are left completely blank, filled entirely with 0 s. The final board should have a structure that looks like this:

Many students find themselves stuck on the exact same error: getting stuck on syntax, trying to print a 2D grid that won't format properly, or struggling to determine when to place a 1 versus a 0 on the board. 916 checkerboard v1 codehs fixed

# Create an 8x8 board filled with 0s board = [[0] * 8 for _ in range(8)] # Use nested for loops to modify specific rows for row in range(8): for col in range(8): # Top 3 rows (0, 1, 2) and bottom 3 rows (5, 6, 7) if row < 3 or row > 4: # Checkerboard condition: sum of indices is even if (row + col) % 2 == 0: board[row][col] = 1 # Print the board using the provided function print_board(board) Use code with caution. Copied to clipboard Initialize the Grid Create an list of lists where every element starts as

A is simply a list where each element is itself another list. This is the perfect data structure for representing a grid.

Most errors in this assignment stem from two specific logical hurdles: Row transitions and grid parity. 1. The "Fencepost" Error to create a checkerboard pattern in the top

: Do not define your print_board function inside another function or loop; it should be at the top level of your script.

A function that moves Karel up to the next row and faces him in the opposite direction.

# 1. Initialize the board with all 0s board = [] for i in range(8): board.append([0] * 8) # 2. Use nested loops to replace 0s with 1s # Goal: Top 3 and bottom 3 rows should have 1s in a checkerboard pattern for row in range(8): for col in range(8): # Check if it's in the top 3 (0-2) or bottom 3 (5-7) rows if row < 3 or row > 4: # Use modulus to create the alternating checkerboard pattern if (row + col) % 2 == 0: board[row][col] = 1 # 3. Print the final board for row in board: print(row) Use code with caution. Copied to clipboard Why this works: # Create an 8x8 board filled with 0s

loops to "spot-fill" the ones where the checker pieces should go. 1. Initialize the 8x8 Grid Start by creating a list of lists where every value is ): board.append([ Use code with caution. Copied to clipboard 2. Use Nested Loops with Assignment

If you try to implement your own logic and are still getting errors, check to ensure you aren't making these common CodeHS mistakes:

The primary challenge lies in the alternating pattern. It cannot simply alternate every single step, because when a row ends, the next row must start with the correct alternating value to create a grid pattern rather than vertical stripes. The Mathematical Logic